RWR-Priority setting
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Here is the RWR on PRIORITY setting:
Note the 6 Su33’s are not showing though I am getting sound warnings.
Switching to OPEN RWR mode they are there:
Also, I experience this at times where Migs right in front of me at all aspects simply do not show up in radar; TWS, RWS and Dogfight.
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MiG-21 has a relatively small RCS and when beaming can vanish inside 10nm. I’d venture a guess that’s what occurred on screen #3.
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Here is the RWR on PRIORITY setting:
Note the 6 Su33’s are not showing though I am getting sound warnings.
Switching to OPEN RWR mode they are there:
Also, I experience this at times where Migs right in front of me at all aspects simply do not show up in radar; TWS, RWS and Dogfight.
3rd picture, your radar range is 40miles, try to set it lower and you may see those mig’s
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Setting the radar range lower doesn’t change whether or not the contacts will show up, it just helps de-clutter the screen if you have a bunch of contacts up close. If you’re trying to engage them, you could always just try chucking an amraam out there maddog and see if it picks one of them up.
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Also you are only scanning down to 4000’ @20 miles range. With those Migs at 10 miles and lower than the horizon they could actually be below your search arc.
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Also you are only scanning down to 4000’ @20 miles range. With those Migs at 10 miles and lower than the horizon they could actually be below your search arc.
I had thought the same thing, but was too lazy to do the math. However, since this was brought up, I’ll go ahead and do it. Put your math hats on everyone
We’ll use SohCahToa for this one. We know the targets are at an angle of 5° below the horizon, and that we are scanning down to 4k feet at 20 miles. That means that we’re looking down 16k feet over 20 nm. (I’m assuming the range on the FCR is in nm and not just miles). The TOA part of SohCahToa tells us that tan(θ) = Opp/Adj.
Our scanning range is our Adjacent segment, and our 16k altitude drop is our Opposite segment. We’ll put everything in feet for this (using 1nm ≈ 6000 ft). That gives us tan(θ) = 16,000/120,000. Simply that fraction and we get tan(θ) = 2/15. Solving for θ, we get θ = arctan(2/15), or roughly 7.6°. That means that we are scanning 7.6° below the horizon, and since are targets are not lower than that, our targets are within the scanning angles.
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yeah they are within the radar parameters. Must be a beaming effect. Also happens in dogfight modes at times including Mig=29’s. Imagine the pucker factor when you have Mig29’s under 10 miles and unable to lock them up…seconds feel like an eternity
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Though if they were actually coming at you, they’d probably show up on the FCR…probably.